Question

若a加3若a+3的绝对值加(b加1的)平方等于零,代数式2a-a+m/3的值比1/2b-a+m多一,求m的值

Answer 1

|a+3|+(b+1)^2=0

则,a+3=0 a=-3

b+1=0 b=-1

(2a-a+m/3)-(1/2b-a+m)=1

(-3+m/3)-(1/2+3+m)=1

(-2/3)m=7

m=-21/2