10吨90%的碘化银中含AgI为10*90% = 9.0吨
其中含Ag:9.0*107.8/(107.8+127) = 4.13吨
设自然界中Ag-107的物质的量的分数为x, Ag-109为1-x: 107x+109(1-x) = 107.8
x = 0.6
4.13吨银中含Ag-107:4.13*0.6 = 2.46吨
题中没给转化率,原料中含109Ag无法计算.假定为100%,则原料中含109Ag: 4.13*0.4 = 1.67吨
10吨90%的碘化银中含AgI为10*90% = 9.0吨
其中含Ag:9.0*107.8/(107.8+127) = 4.13吨
设自然界中Ag-107的物质的量的分数为x, Ag-109为1-x: 107x+109(1-x) = 107.8
x = 0.6
4.13吨银中含Ag-107:4.13*0.6 = 2.46吨
题中没给转化率,原料中含109Ag无法计算.假定为100%,则原料中含109Ag: 4.13*0.4 = 1.67吨