原式=（1/2010*1/2009*1/2008*...*1/3*1/2*1*2010*2009*2008*...*3*2*1)^2011
=(1/2010*2010...1/2*2)^2011
=1
(1/2010*1/2009*1/2008*...*1/3*1/2*1)^2011*(2010*2009*2008*..
2个回答
相关问题
-
计算|1/2011-1/2010|+|1/2010-1/2009|+|1/2009-1/2008|-|1/2008-1/
-
计算 |1/2011-1/2010|+|1/2010-1/2009|+|1/2009-1/2008|+...+|1/3-
-
2010*2010-2009*2009+2008*2008···················+2*2-1*1
-
(2009×2010-1)/(2009+2008×2010)+(2010×2011-1)/(2010+2009×2011
-
2010+2009×2011/2010×2011-1—2009+2008×2010/2009×2010-1
-
计算|1/2011-1/2010|+|1/2010-1/2009|+|1/2009-1/2008|+...+|1/2-1
-
2008+2007x2009/2008x2009-1+2009+2008x2010/2009x2010-1+2010+2
-
简算:1/(2007+2008)+1/(2008+2009)+1/(2010+2011)+2011
-
1*2*3*...*2009*2010.还有：2009/2008*2008/2007*...*2/3*2/1.
-
计算丨1/2008-1/2009丨+丨1/2009-1/2010丨+丨1/2010-1/2011丨