Question

(4/x-5)+(x-3)/(12-x)=(x-45)/(x^2-17x+60)

Answer 1

(4/x-5)+(x-3)/(12-x)=(x-45)/(x^2-17x+60)

(4/x-5)+(x-3)/(12-x)=(x-45)/(x-5)(x-12)

通分,两边同乘以(x-5)(x-12)得

4(x-12)-(x-3)(x-5)=x-45

-x^2+11x-18=0

x^2-11x+18=0

(x-2)(x-9)=0

x=2或x=9

经检验,都是方程的根!