Question

f(x)=x四次方-11x三次方+36x二次方-16x-64

Answer 1

x四次方-11x三次方+36x二次方-16x-64

=x^4-11x³+28x²+8x²-16x-64

=x²(x²-11x+28)+8(x²-2x-8)

=x²(x-4)(x-7)+8(x-4)(x+2)

=(x-4)(x³-7x²+8x+16)

=(x-4)(x³-7x²-8x+16x+16)

=(x-4)[(x(x²-7x-8)+16(x+1)]

=(x-4)[x(x-8)(x+1)+16(x+1)]

=(x-4)(x+1)(x²-8x+16)

=(x-4)³(x+1)