Question

如图,在△ABC中,∠B=∠ACB,CD平分∠ACB交AB于dianD

Answer 1

∠BDE=∠CDE=∠A,

所以∠BDC=2∠A

又因为∠BDC=∠A+∠ACD

所以∠A=∠ACD,即∠ACB=2∠A

所以∠A=36°

∠B=∠ACB=72°