(1/8a^3b^2c-4a^2b^3)(2a^2bc)^3
=(1/8a^3b^2c-4a^2b^3)(8a^6b^3c^3)
=a^9b^5c^4-1/2a^8b^3c^3
追问(1/8a^3b^2c-4a^2b^3)(2a^2bc)^3
1个回答
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