(Ⅰ) ( a 1 +d)( a 1 +4d)=55 2 a 1 +8d=22 解得a 1 =3,d=2∴a n =3+(n-1)×2=2n+1(Ⅱ)当n≥2时,b n =a n -a n-1 =2,b 1 =3∴c n =b n •2 n S n =3×2+2×...
设等差数列{a n }的公差为d(d>0),且满足:a 2 •a 5 =55,a 4 +a 6 =22.
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