(2ax²-x²+3x+2)-(5x²-4x²+3x)
=2ax²-x²+3x+2-5x²+4x²-3x
=(2a-2)x²+2
值与X无关
所以带x的项系数为0
所以2a-2=0
a=1
所以原式=2a³+3a²+4a-5+a
=2a³+3a²+5a-5
=2+3+5-5
=5
(2ax²-x²+3x+2)-(5x²-4x²+3x)
=2ax²-x²+3x+2-5x²+4x²-3x
=(2a-2)x²+2
值与X无关
所以带x的项系数为0
所以2a-2=0
a=1
所以原式=2a³+3a²+4a-5+a
=2a³+3a²+5a-5
=2+3+5-5
=5