Question

亟待解决!高三数学圆锥曲线题目!（请用高中知识解答,谢谢!）

Answer 1

设直线方程为 y = k(x-1), 椭圆为y^2 = 1 - x^2/2(k^2 + 1/2)x^2 -2k^2 x + k^2 - 1 = 0解得A,B的x 坐标为Ax = (2k^2 + 根号（4k^4 - 4(k^2-1)(k^2 + 1/2)))/(2(k^2+1/2))Bx = (2k^2 - 根号（4k^4 - 4(k^2-1)(k...