已知x=1/(1+根号2),先化简1/(x+1)+ - 知识问答

已知x=1/(1+根号2),先化简1/(x+1)+(根号x平方-2x+1)/(x-1)

1个回答

x=1/(1+根号2)=√2-1
1/(x+1)+(根号x平方-2x+1)/(x-1)
=1/（x+1)+|(x-1)|/(x-1)
=1/（x+1)-(x-1)/(x-1)
=1/(x+1）
=√2/2

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