Question

(x+1)(x²+1)(x⁴+1 )(x的八次方+1)(x的十六次方+1)

Answer 1

原式=(x-1)(x+1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)/(x-1)

=(x^2-1)(x^2+1)(x^4+1)(x^8+1)(x^16+1)/(x-1)

=(x^4-1)(x^4+1)(x^8+1)(x^16+1)/(x-1)

=(x^8-1)(x^8+1)(x^16+1)/(x-1)

=(x^16-1)(x^16+1)/(x-1)

=(x^32-1)/(x-1)