=lim(x→∞)e^x / e^x^2·ln[(1+1/x)]
=e^ lim(x→∞) (x - x^2·ln[(1+1/x)])
令u=1/x,则u→0.
原式=e^ lim(u→0) (1/u - ln[(1+u)] /u²)
=e^ lim(u→0) ( (u - ln[(1+u)] ) /u²)
=e^ lim(u→0) ( (1 - 1/(1+u) ) /2u)
=e^ lim(u→0) ( 1/[2(1+u)] )
=e^(1/2)
即√e
=lim(x→∞)e^x / e^x^2·ln[(1+1/x)]
=e^ lim(x→∞) (x - x^2·ln[(1+1/x)])
令u=1/x,则u→0.
原式=e^ lim(u→0) (1/u - ln[(1+u)] /u²)
=e^ lim(u→0) ( (u - ln[(1+u)] ) /u²)
=e^ lim(u→0) ( (1 - 1/(1+u) ) /2u)
=e^ lim(u→0) ( 1/[2(1+u)] )
=e^(1/2)
即√e