Question

基本不等式问题当X>0时可得到不等式X+(1/X)>=2,X+(4/X^2)>=3.由此推广X+(A/X^N)>=N+1

Answer 1

A= n^n

X+(N/X^N)

= N*X/N +(A/X^N)

>= (N+1) * [N^N*x^N/(N^N*x^N] ^(1/N+1)

= N+1