因为,∠BOE=90°OD平分∠BOE:
所以:∠BOD=45°
∠BOC+∠COD=∠BOD=45°∠BOC=2∠COD
2∠COD+∠COD=45°
3∠COD=45°
∠COD=15°
∠BOC=30°
BO平分∠AOC ,∠BOC=30°
∠AOB =30°
∠AOE=∠AOB+∠BOE
=30°+90°
=120°
所以∠AOE=120°
因为,∠BOE=90°OD平分∠BOE:
所以:∠BOD=45°
∠BOC+∠COD=∠BOD=45°∠BOC=2∠COD
2∠COD+∠COD=45°
3∠COD=45°
∠COD=15°
∠BOC=30°
BO平分∠AOC ,∠BOC=30°
∠AOB =30°
∠AOE=∠AOB+∠BOE
=30°+90°
=120°
所以∠AOE=120°