5x^2-3xy-4y^2-11xy-7x^2+2y^2
=-2x²-2y²-14xy
=-2(x²+y²）-14xy
=-2×7-14×（-2）
=-14+28
=14
x^2+y^2=7,xy=-2,求多项式5x^2-3xy-4y^2-11xy-7x^2+2y^2的值
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