4m²-12mn+4m-6n+9n²-24因式分解
3个回答
4m²-12mn+4m-6n+9n²-24
=4m²-12mn+9n²+4m-6n-24
=(2m-3n)²+2(2m-3n)-24
=(2m-3n+6)(2m-3n-4)
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已知mn是实数且满足4m²+9n²-4m+6n+2=0那么18n²+24n+4比4m&su
是否存在整数m,n,使得m²+4mn+4n²+6m+12n=1986
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(m²-6mn+9n²)÷(m-3n)-(4m²-9n²)-(2m-3n)怎么做