设材料密度为ρ,大球体积V1,左边力臂L1,小球体积V2,右边力臂L2
假设实心
ρV1gL1=ρV2gL2
V1L1=V2L2
(ρV1g-ρ水V1g)L1-(ρV2g-ρ水V2g)L2
=ρV1gL1-ρV2gL2+ρ水V2gL2-ρ水V1gL1
=ρ水g(V2L2-V1L1)
=0
所以依然能够平衡,A正确
BCD均可等效看作是密度不等的实心球,设密度分别为ρ1、ρ2
ρ1V1gL1=ρ2V2gL2
ρ1V1L1=ρ2V2L2
V1L1≠V2L2
(ρ1V1g-ρ水V1g)L1-(ρ2V2g-ρ水V2g)L2
=ρ1V1gL1-ρ2V2gL2+ρ水V2gL2-ρ水V1gL1
=ρ水g(V2L2-V1L1)
≠0
所以不能平衡,排除BCD
选A