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已知:Fe(s)+1/2O 2 (g)==FeO(s) △H=-272 kJ·mol -1 2Al(s)+3/2O 2
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相关问题
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已知下列数据:Fe(s)+1/2O 2 (g) =FeO(s) △H=-272kJ·mol -1 2Al(s)+3/2O
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(1)已知:Fe(s)+[1/2]O2(g)=FeO(s)△H=-272.0kJ•mol-12Al(s)+[3/2]O2
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已知反应:①Fe(s)+CO 2 (g) FeO(s)+CO(g) △H=a kJ·mol -1 ;②Fe(s)+H 2
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反应①Fe(s)+CO 2 (g) FeO(s)+CO(g) △H1=a kJ/mol;②CO(g)+1/2O 2 (g
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反应①Fe(s)+CO 2 (g) FeO(s)+CO(g) △H1=a kJ/mol;②CO(g)+1/2O 2 (g
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已知:Fe2O3(s)+[3/2]C(s)═[3/2]CO2(g)+2Fe(s)△H=+234.1kJ/mol
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已知:Fe 2 O 3 (s)+3/2C(s)=3/2CO 2 (g)+2Fe(s) △H= +234.1kJ·mol
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(1)已知热化学方程式:4Al(s)+3O2(g)═2Al2O3 (s)△H1=-3288.6kJ•mol-1
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.已知:Fe2O3(s)+3/2C(s)=3/2CO2(g)+2Fe(s) ΔH=+234.1 kJ/mol
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设反应①Fe(s)+CO 2 (g) FeO(s)+CO(g) ΔH="a" kJ/mol,反应②Fe(s)+H 2 O