Question

数学题,高手进（相似三角形）如图,小明小刚站在路灯AB下,且点bdfg在同一直线,测得小明的影长df=3m,小刚的影长f

Answer 1

(1) ∵△HFG∽△ABG

∴HF/AB=FG/BG

∴1.88/AB=5/(BD+8) 5AB=1.88(BD+8) (1)

∵△CDF∽△ABF

∴CD/AB=DF/BF

∴1.6/AB=3/(BD+3) BD=(3AB/1.6)-3 代入(1)

AB=6.37m

BD=8.94m

(2) ∵△CHM∽△CKN

∴HM/KN=CM/MN

∴(1.88-1.6)/KN=3/5

KN=5*0.28/3=0.47m

KG=KN+NG=1.6+0.47=2.07m

∵△KGP∽△ABP

∴KG/AB=GP/BP

∴2.07/6.37=GP/(GP+8.94+8)

GP=8.15m