根据题意得
a-1=0 ab-2=0
解得
a=1 b=2
于是
1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2005)(b+2005)
=1/1x2+1/2x3+1/3x4+...+1/2006x2007
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/2006-1/2007)
=1-1/2+1/2-1/3+1/3-1/4+...+1/2006-1/2007
=1-1/2007
=2006/2007
根据题意得
a-1=0 ab-2=0
解得
a=1 b=2
于是
1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)+……+1/(a+2005)(b+2005)
=1/1x2+1/2x3+1/3x4+...+1/2006x2007
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+...+(1/2006-1/2007)
=1-1/2+1/2-1/3+1/3-1/4+...+1/2006-1/2007
=1-1/2007
=2006/2007