= [(x+3)(x-3)-7]/(x-3) 2(x-3)/(x²-8x+4²)
= 2 (x²-4²) / (x-4)²
=2(x+4)(x-4)/(x-4)²
=2(x+4)/(x-4)
当x=2^-3=1/8时
原式=2(1/4+4)/(1/4-4)
=-66/31
= [(x+3)(x-3)-7]/(x-3) 2(x-3)/(x²-8x+4²)
= 2 (x²-4²) / (x-4)²
=2(x+4)(x-4)/(x-4)²
=2(x+4)/(x-4)
当x=2^-3=1/8时
原式=2(1/4+4)/(1/4-4)
=-66/31