解1:
(2^m)×32×(4^m)=2^20
(2^m)×(2^5)×[(2^2)^m]=2^20
(2^m)×(2^5)×[2^(2m)]=2^20
[2^(m+2m+5)]=2^20
[2^(3m+5)]=2^20
3m+5=20
m=5
(-m³)²÷(-m)³
=(-5³)²÷(-5)³
=(5^6)÷(-5³)
=-5^(6-3)
=-5³
=-125
解1:
(2^m)×32×(4^m)=2^20
(2^m)×(2^5)×[(2^2)^m]=2^20
(2^m)×(2^5)×[2^(2m)]=2^20
[2^(m+2m+5)]=2^20
[2^(3m+5)]=2^20
3m+5=20
m=5
(-m³)²÷(-m)³
=(-5³)²÷(-5)³
=(5^6)÷(-5³)
=-5^(6-3)
=-5³
=-125