5x^2-3xy+1/2y^2-2x+1/2y+1/4=0
乘以4通分之后得到：
20x^2-12xy+2y^2-8x+2y+1=0
（4x-y)^2+(2x-y)^2-2(4x-y)+1=0
(4x-y-1)^2+(2x-y)^2=0
得 4x-y-1＝0
2x-y＝0
解得：x=1/2 ,y=1
已知实数x,y满足5x^2-3xy+1\2y^2-2x+1\2y+1\4=0,求x,y的值
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