{3x-2y+5z=02x+5y-10z=192x+3y+15z=13{x+y=3y+z=5x+z=6

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  • 3x-2y+5z=0 (1)

    2x+5y-10z=19 (2)

    2x+3y+15z=13 (3)

    (2)-(3) 得2y-25z=6 (4)

    (2)*3-(1)*2得19y-40z=57 (5)

    (4)*19-(5)*2得z=0

    将z=0带入(4)得y=3

    将y=3、z=0带入(3)得x=2

    所以 x=2

    y=3

    z=0

    补充:x+y=3 (1)

    y+z=5 (2)

    x+z=6 (3)

    〔(1)+(2)+(3)〕÷2 得 x+y+z=7 (4)

    (4)-(1)得 z=4

    (4)-(2)得 x=2

    (4)-(3)得 y=1