计算:(1)根号1/3*根号12-根号75)(2)2倍根号3-根号3*1/2倍根号5除2倍根号20

4个回答

  • (1)根号1/3*根号12-根号75

    =(根号3/3)*2倍根号3-5倍根号3

    =2-5倍根号3

    (2)2倍根号-根号3*1/2倍根号5除2倍根号20

    =2倍根号3-根号3*1/2*1/4

    =2倍根号3-根号3/8

    =根号3*(2-1/8)

    =15根号3/8

    呃,最上面那位第一题错了.顺便答一下你后来问的.

    (1)(2倍根号3-3倍根号2)(2倍根号3+3倍根号2)

    =(2倍根号3)²-(3倍根号2)²

    =4*3-9*2

    =-6

    (2)(1-2倍根号3)(1+2倍根号3)-(2倍根号3-1)的平方+2(根号5+根号3)

    =1²-(2倍根号3)²-【(2倍根号3)²+1²-2*2倍根号3】+2倍根号5+2倍根号3

    =1-4*3-【4*3+1-4倍根号3】+2倍根号5+2倍根号3

    =1-12-12-1+4倍根号3+2倍根号5+2倍根号3

    =-24+根号3(4+2)+2倍根号5

    =-24+6倍根号3+2倍根号5

    提醒一下,是-24,不是正的呃