Question

已知正弦交流电压U1=6 2 sin(100∏t+90°)V,U2=82 sin(100∏t)V,试计算:(1) U1+

Answer 1

(1)U1+U2=

6*根号2sin(100派t+90)+8*根号2sin(100派t)

=-6*根号2cos(100派t)+8*根号2sin(100派t)

=10*根号2[-3cos(100派t)/5+4sin(100派t)/5]

=(10*根号2)*sin(100派t-53度)

(2)U1-U2

6*根号2sin(100派t+90)-8*根号2sin(100派t)

=-6*根号2cos(100派t)-8*根号2sin(100派t)

=-10*根号2[3cos(100派t)/5+4sin(100派t)/5]

=-(10*根号2)*sin(100派t+53度)