Question

帮忙解一个一元二次方程（1＋根2)y平方-(1-根2)y=0有点麻烦,我不会输根号谢谢大家谢谢了过程能给详细一点吗

Answer 1

(1+√2)y^2-(1-√2)y=0

y[(1+√2)y-(1-√2)]=0

y1=0

y2=(1-√2)/(1+√2)=(1-√2)^2/(1+√2)/(1-√2)=-3+2√2