设公差为d,则S3=3a1+3d=6,a3=a1+2d=8,解之可得:a1=-4,d=6 S12-S9=a12+a11+a10=3a1+30d=168 a3=a1+2d=8,s3=3a1+3d,
等差数列an的前几项和为Sn,已知S3=6,a1=11,则公差d等于
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