Question

∫(0,x)e^(-t^2)dt求函数在x=0处的幂级数展开式,并确定收敛范围

Answer 1

f(x)=∫(0,x)e^(-t^2)dtf'(x)=e^(-x^2)设-x^2=kx=√-kf'(√-k)=E（E上：无穷大）(E下：n=0) (k^n)/n!K属于（-无穷大,+无穷大）(当然,你要先说明R（√-k）=0（n->无穷大）才可以把它化成泰勒级数形式)f'(x)=E[（E上：...