1)3(x-3)=(x-3)²
(x-3)²-3(x-3)=0
(x-3)(x-3-3)=0
x1=3 x2=6
2)4x²-(x-1)²=0
(2x+x-1)[2x-(x-1)]=0
(3x-1)(x+1)=0
x1=1/3 x2=-1