log9^5=a,log3^7=b
LOG(3,7)=2LOG(9,7)=B
==>LOG(9,7)=B/2
lOG(35,9)=1/LOG(9,35)=1/(LOG(9,7)+LOG(9,5))=1/(B/2+A)=2/(B+2A)
log9^5=a,log3^7=b,求log35^9=?
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