答：（1）方程2x²-6x+3=0根据韦达定理有：x1+x2=6/2=3x1*x2=3/2x1²+x2²=(x1+x2)²-2x1*x2=3²-2*3/2=6（2）x1=√3+√2,x2=√3-√2x1+x2=2√3x1*x2=3-2=1所以：方程为x²-2√3x+1=0（3）x...
答：（1）方程2x²-6x+3=0根据韦达定理有：x1+x2=6/2=3x1*x2=3/2x1²+x2²=(x1+x2)²-2x1*x2=3²-2*3/2=6（2）x1=√3+√2,x2=√3-√2x1+x2=2√3x1*x2=3-2=1所以：方程为x²-2√3x+1=0（3）x...