(y-y1)/(y2-y1)=(x-x1)/(x2-x1)与(y-y1)/(x-x1)=(y2-y1)/(x2-x1)的
2个回答
等式两边同时除于(y2-y1) 就得到了
(y-y1) / (y2-y1) = (x-x1) / (x2-x1) *1
所以图像相同
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