Question

已知m的平方+m-1=0,则m的三次方+2m的平方+2020=____.

Answer 1

m^2+m-1=0

所以 m*（m^2+m-1）= 0

m^3+m^2-m=0

得 m^3+m^2=m

所以 m^3+2m^2+2020=m+m^2+2020=m^2+m-1+2021=0+2021=2021