F(x)=2sinxcos(x+π/6)-cos2x+m
= sin(2x+π/6) - sin(π/2-2x) + m - sin(π/6)
= 2*sin(2x - π/6)*cos(π/3) + m - sin(π/6)
= sin(2x - π/6) + m - 1/2
F(x)最小值为:m - 3/2;
m = -1.5
F(x)=2sinxcos(x+π/6)-cos2x+m
= sin(2x+π/6) - sin(π/2-2x) + m - sin(π/6)
= 2*sin(2x - π/6)*cos(π/3) + m - sin(π/6)
= sin(2x - π/6) + m - 1/2
F(x)最小值为:m - 3/2;
m = -1.5