Question

请问 方程组的通解是什么?

Answer 1

(1 -1 -1 1

1 -1 1 -3

3 -3 -2 1)

等价

(1 -1 -1 1

0 0 2 -4

0 0 1 -2)

等价

(1 -1 -1 1

0 0 1 -2

0 0 1 -2)

等价

(1 -1 0 -1

0 0 1 -2

0 0 0 0)

即

x1=x2 +x4

x2=x2

x3= 2x4

x4= x4

所以

通解为

x=c1(1,1,0,0)T+c2(1,0,2,1)T