∠1加∠2=2∠A
设虚线交点为A',则∠2+∠ADE+∠EDA'=∠1+∠AED+∠DEA'=180°=∠A+∠ADE+∠AED=∠A'(=∠A)+∠DEA'(=∠AED)+∠EDA'(=∠ADE),化简即得∠1加∠2=2∠A.