Question

1 实验室制取Cl2的化学方程式为MnO2 + 4HCl=MnCl2 + Cl2↑+ 2H2O,当有146.0克HCl完

Answer 1

1.

146/36.5=4

(1)4/2=2

(2)4/4=1

(3)(4/4)*(55+71)=126g

(4)(4/4)*22.4=22.4L

2.

(1)Fe+Cu(2+)=Fe(2+)+Cu

(2)(46.6-45)*(56+96)/(64-56)=30.4

(30.4/152)/0.1=2mol/L

3.H2SO4+BaCl2=BaSO4()+2HCl

4.66/(137+96)=0.02

c(H2SO4)=0.02/0.01=2

HCl+NaOH=NaCl+H2O

(2*35/1000)-0.04=0.03

c(HNO3)=0.03/0.01=3mol/L

HNO3+NaOH=NaNO3+H2O