(x³+3x²y-2xy²-1)+(-xy²+x²y-2x³+3)+(x³-4x²y+3xy²-8)
=x³+3x²y-2xy²-1-xy²+x²y-2x³+3+x³-4x²y+3xy²-8
=-1+3-8
=-6
所以无论xy为多少,原式的只都是-6.
(x³+3x²y-2xy²-1)+(-xy²+x²y-2x³+3)+(x³-4x²y+3xy²-8)
=x³+3x²y-2xy²-1-xy²+x²y-2x³+3+x³-4x²y+3xy²-8
=-1+3-8
=-6
所以无论xy为多少,原式的只都是-6.