Question

求函数y=ln(x+根号(1+x^2))微分,以及函数y=ln(2x+根号(1+x^2))微分,

Answer 1

syms x

>> y=log(x+sqrt(1+x^2));

>> simple(diff(y)

ans =

1/(1+x^2)^(1/2)

>>y=log(2*x+sqrt(1+x^2));

>>simple(diff(y))

ans =

(2+1/(1+x^2)^(1/2)*x)/(2*x+(1+x^2)^(1/2))

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