Question

已知﹙x-1﹚的算术平方根+﹙y+3﹚2次方+﹙x+y+z﹚的算术平方根=0,求﹙y+z﹚的值.

Answer 1

﹙x-1﹚的算术平方根+﹙y+3﹚2次方+﹙x+y+z﹚的算术平方根=0

则x-1=0,y+3=0,x+y+z=0

x=1,y=-3,z=2

y+z=-1