f(1) = 1,lim(x->1-) f(x) = lim(x->1-) x² = 1,lim(x->1+) f(x) = lim(x->1+) (ax+b) = a+b
f(x)在x=1处连续 => a+b =1,b = 1-a
在x=1的左导数 f - '(1) = lim(x->1-) (x² -1)/(x-1) = 2,
右导数 f-'(1) = lim(x->1-) (ax+1-a -1)/(x-1) = a
=> a = 2,b = -1
f(1) = 1,lim(x->1-) f(x) = lim(x->1-) x² = 1,lim(x->1+) f(x) = lim(x->1+) (ax+b) = a+b
f(x)在x=1处连续 => a+b =1,b = 1-a
在x=1的左导数 f - '(1) = lim(x->1-) (x² -1)/(x-1) = 2,
右导数 f-'(1) = lim(x->1-) (ax+1-a -1)/(x-1) = a
=> a = 2,b = -1