答:
不妨设│PF1│-│PF2│=2a=6
│PF1│*│PF2│=32
│PF1│^2+│PF2│^2=100
│F1F2│=10
cos∠F1PF2=(│PF1│^2+│PF2│^2-│F1F2│^2)/2│PF1│*│PF2│
=0
∠F1PF2=π/2
PF1⊥PF2
答:
不妨设│PF1│-│PF2│=2a=6
│PF1│*│PF2│=32
│PF1│^2+│PF2│^2=100
│F1F2│=10
cos∠F1PF2=(│PF1│^2+│PF2│^2-│F1F2│^2)/2│PF1│*│PF2│
=0
∠F1PF2=π/2
PF1⊥PF2