令2^A=3^B=6^C=D
则A=logD/log2;B=logD/log3;C=logD/log6
则ab-bc=(logD/log2)*(logD/log3)-(logD/log3)*(logD/log6)
=logD*logD(log6-log2)/(log2*log3*log6)
=logD*logD*(log(6/2))/(log2*log3*log6)
=logD*logD*log3/(log2*log3*log6)
=logD*logD/(log2*log6)
=(logD/log2)*(logD/log6)
=AC