在三角形ABD和三角形ACD中,∠ABD=∠ACD ∠ADB=∠ACD=90°AB=AC,所以△ABD≡△ACD,所以BD=DC ∠BAD=∠CAD
已知:如图,△ABC是等腰三角形,AB=AC,AD是高,求证:BD=DC;∠BAD=∠CAD
1个回答
相关问题
-
已知:如图所示,在△ABC中,∠BAD=∠CAD,BD=DC,求证:AB=AC
-
如图,△ABC中,AB=AC,AD是高,求证:∠BAD=∠CAD.
-
如图,△ABC中,AB=AC,AD是高,求证:∠BAD=∠CAD.
-
如图,△ABC中,AB=AC,AD是高,求证:∠BAD=∠CAD.
-
如图,△ABC中,AB=AC,AD是高,求证:∠BAD=∠CAD.
-
如图,在三角形ABC中,AB=AC,AD是高,求证1:AB=DC 2:角BAD=角CAD 要过
-
已知如图△ABC中,∠BAD=∠CAD求证AB/AC=BD/CD
-
如图,已知三角形ABC中,AD是角平分线,求证:BD/DC=AB/AC
-
已知:如图,AD平分∠BAC,DE⊥AB,DF⊥AC,DB=DC,求证:△ABC是等腰三角形.
-
几何数学题:如图在△ABC,∠BAD=∠CAD,AD=DB,DC⊥AC.求证:AB=2AC