若实数x y满足根号x+y-2 + 根号y-2x+3=0,求2y-x+1的值
1个回答
根号x+y-2 + 根号y-2x+3=0,
x+y-2=0
y-2x+3=0
解得:
x=5/3
y=1/3
2y-x+1=2/3-5/3+1=0
相关问题
若实数X,Y满足Y=根号(2X-1)+根号(1-2X)+2,求X,Y的值
若实数x,y满足[x+根号(x^2+1)][y+根号(y^2+1)]=1,求x+y
若实数x,y满足x根号(1-x)=根号(y-2)+根号(x-1),求3x²+xy-y²/x²
若实数x,y满足x²+y²-4x-2y+5=0,则根号下x+y/根号下3y-2根号下x的值是( )
若实数X.Y满足y=根号2x-1+根号1-2x+1/3求代数式(x-y)的平方
已知实数x,y满足x2+y2-4x-2y+5=0则(根号x+y)/根号(3y-2根号x)的值
已知实数x,y满足下x^2+根号2y=根号3,y^2+根号2x=根号3,求x/y+y/x
若实数x,y满足x²+y²-10x-2y+26=0 ,求根号下x²y²的值
已知实数x,y满足根号2x-y的值+5x-6=y-根号y-2x,求x,y的值
已知实数x y,满足y=根号(x²-4)+根号(4-x²)+1 除以x-2 求2x-3y的值