Question

若m等于他它的倒数,则分式m^2+6m+9/m-2÷m+3/m^2-2m的值为?

Answer 1

m等于他它的倒数--------->m=1

m^2+6m+9/m-2÷m+3/m^2-2m

=(m+3)^2/(m-2)*m(m-2)/(m+3)

=(m+3)m

=(1+3)*1

=4