Question

y=(x+y)的n次方求导怎么做?

Answer 1

y=(x+y)^n,

两边对x求导,得

y'=n[(x+y)^(n-1)]*(1+y'),

∴{1-n[(x+y)^(n-1)]}y'=n[(x+y)^(n-1)],

∴y'=n[(x+y)^(n-1)]/{1-n[(x+y)^(n-1)]}.