Question

已知抛物线y=x2+x-1与直线y=kx+2交于点坐标为（m,1）,求k,m的值.

Answer 1

由题意,得

1=m^2+m-1

m^2＋m-2=0

(m+2)(m-1)=0

m=-2或m=1

1.m=-2

1=-2k+2

2k=1

k=1/2

2.m=1

k+2=1

k=-1